In the diagram, A, B, C, and D represent the positions of 4 towns. AB = 12km, BC = 9km and
D is due north of A. The bearings of B from A and D are
respectively. Find(a) the distance AC,
(b) the bearing of C from A
(c) the distance BD
(d) the shortest distance from B to a road running along AD.
Try to attempt to this question. Answer will be posted by end of the week.
Complete solution of the question
No comments:
Post a Comment